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3212079675841 = 11328425483857
BaseRepresentation
bin101110101111011110110…
…111100011100111000001
3102101001221100121002000001
4232233132313203213001
5410111314344111331
610455335315000001
7451031220520651
oct56573667434701
912331840532001
103212079675841
111029265269153
1243a632b99001
131a3b8965c55a
14b1673416361
1558848426561
hex2ebdede39c1

3212079675841 has 4 divisors (see below), whose sum is σ = 3240505159812. Its totient is φ = 3183654191872.

The previous prime is 3212079675839. The next prime is 3212079675877. The reversal of 3212079675841 is 1485769702123.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1434401452225 + 1777678223616 = 1197665^2 + 1333296^2 .

It is a cyclic number.

It is not a de Polignac number, because 3212079675841 - 21 = 3212079675839 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3212079675821) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14212741816 + ... + 14212742041.

It is an arithmetic number, because the mean of its divisors is an integer number (810126289953).

It is a 1-persistent number, because it is pandigital, but 2⋅3212079675841 = 6424159351682 is not.

Almost surely, 23212079675841 is an apocalyptic number.

It is an amenable number.

3212079675841 is a deficient number, since it is larger than the sum of its proper divisors (28425483971).

3212079675841 is a wasteful number, since it uses less digits than its factorization.

3212079675841 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28425483970.

The product of its (nonzero) digits is 5080320, while the sum is 55.

The spelling of 3212079675841 in words is "three trillion, two hundred twelve billion, seventy-nine million, six hundred seventy-five thousand, eight hundred forty-one".

Divisors: 1 113 28425483857 3212079675841