Base | Representation |
---|---|
bin | 1001010110010011101… |
… | …10100011001010010001 |
3 | 1010201002221222222020201 |
4 | 10223021312203022101 |
5 | 20230321302200423 |
6 | 403321432535201 |
7 | 32130661541614 |
oct | 4531166431221 |
9 | 1121087888221 |
10 | 321214100113 |
11 | 114253a92745 |
12 | 52305b51501 |
13 | 243a0bc687a |
14 | 1179278817b |
15 | 854eced2ad |
hex | 4ac9da3291 |
321214100113 has 8 divisors (see below), whose sum is σ = 323278792928. Its totient is φ = 319150554624.
The previous prime is 321214100107. The next prime is 321214100153. The reversal of 321214100113 is 311001412123.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 321214100113 - 29 = 321214099601 is a prime.
It is a super-2 number, since 2×3212141001132 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (321214100153) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 278470 + ... + 848512.
It is an arithmetic number, because the mean of its divisors is an integer number (40409849116).
Almost surely, 2321214100113 is an apocalyptic number.
It is an amenable number.
321214100113 is a deficient number, since it is larger than the sum of its proper divisors (2064692815).
321214100113 is a wasteful number, since it uses less digits than its factorization.
321214100113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 573663.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 321214100113 its reverse (311001412123), we get a palindrome (632215512236).
The spelling of 321214100113 in words is "three hundred twenty-one billion, two hundred fourteen million, one hundred thousand, one hundred thirteen".
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