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32121412153 is a prime number
BaseRepresentation
bin11101111010100101…
…011101101000111001
310001220121002210202121
4131322211131220321
51011241040142103
622431213201241
72214666332635
oct357245355071
9101817083677
1032121412153
1112693777416
126285490221
13304ba3c06c
1417aa0a9dc5
15c7eec06bd
hex77a95da39

32121412153 has 2 divisors, whose sum is σ = 32121412154. Its totient is φ = 32121412152.

The previous prime is 32121412139. The next prime is 32121412159. The reversal of 32121412153 is 35121412123.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32117299369 + 4112784 = 179213^2 + 2028^2 .

It is a cyclic number.

It is not a de Polignac number, because 32121412153 - 25 = 32121412121 is a prime.

It is not a weakly prime, because it can be changed into another prime (32121412159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16060706076 + 16060706077.

It is an arithmetic number, because the mean of its divisors is an integer number (16060706077).

Almost surely, 232121412153 is an apocalyptic number.

It is an amenable number.

32121412153 is a deficient number, since it is larger than the sum of its proper divisors (1).

32121412153 is an equidigital number, since it uses as much as digits as its factorization.

32121412153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1440, while the sum is 25.

Adding to 32121412153 its reverse (35121412123), we get a palindrome (67242824276).

The spelling of 32121412153 in words is "thirty-two billion, one hundred twenty-one million, four hundred twelve thousand, one hundred fifty-three".