Base | Representation |
---|---|
bin | 101110101111100111011… |
… | …110001000000000010001 |
3 | 102101002022102011201011121 |
4 | 232233213132020000101 |
5 | 410112113321112423 |
6 | 10455401512242241 |
7 | 451034622346045 |
oct | 56574736100021 |
9 | 12332272151147 |
10 | 3212224004113 |
11 | 1029329787113 |
12 | 43a6733a0381 |
13 | 1a3bb05239b7 |
14 | b1688666025 |
15 | 58855e3545d |
hex | 2ebe7788011 |
3212224004113 has 2 divisors, whose sum is σ = 3212224004114. Its totient is φ = 3212224004112.
The previous prime is 3212224004071. The next prime is 3212224004137. The reversal of 3212224004113 is 3114004222123.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2055186022464 + 1157037981649 = 1433592^2 + 1075657^2 .
It is a cyclic number.
It is not a de Polignac number, because 3212224004113 - 221 = 3212221906961 is a prime.
It is not a weakly prime, because it can be changed into another prime (3212224005113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1606112002056 + 1606112002057.
It is an arithmetic number, because the mean of its divisors is an integer number (1606112002057).
Almost surely, 23212224004113 is an apocalyptic number.
It is an amenable number.
3212224004113 is a deficient number, since it is larger than the sum of its proper divisors (1).
3212224004113 is an equidigital number, since it uses as much as digits as its factorization.
3212224004113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 3212224004113 its reverse (3114004222123), we get a palindrome (6326228226236).
The spelling of 3212224004113 in words is "three trillion, two hundred twelve billion, two hundred twenty-four million, four thousand, one hundred thirteen".
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