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3212224004113 is a prime number
BaseRepresentation
bin101110101111100111011…
…110001000000000010001
3102101002022102011201011121
4232233213132020000101
5410112113321112423
610455401512242241
7451034622346045
oct56574736100021
912332272151147
103212224004113
111029329787113
1243a6733a0381
131a3bb05239b7
14b1688666025
1558855e3545d
hex2ebe7788011

3212224004113 has 2 divisors, whose sum is σ = 3212224004114. Its totient is φ = 3212224004112.

The previous prime is 3212224004071. The next prime is 3212224004137. The reversal of 3212224004113 is 3114004222123.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2055186022464 + 1157037981649 = 1433592^2 + 1075657^2 .

It is a cyclic number.

It is not a de Polignac number, because 3212224004113 - 221 = 3212221906961 is a prime.

It is not a weakly prime, because it can be changed into another prime (3212224005113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1606112002056 + 1606112002057.

It is an arithmetic number, because the mean of its divisors is an integer number (1606112002057).

Almost surely, 23212224004113 is an apocalyptic number.

It is an amenable number.

3212224004113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3212224004113 is an equidigital number, since it uses as much as digits as its factorization.

3212224004113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 3212224004113 its reverse (3114004222123), we get a palindrome (6326228226236).

The spelling of 3212224004113 in words is "three trillion, two hundred twelve billion, two hundred twenty-four million, four thousand, one hundred thirteen".