Base | Representation |
---|---|
bin | 101110101111101100010… |
… | …000100011010100001010 |
3 | 102101002112000022210101002 |
4 | 232233230100203110022 |
5 | 410112244402111132 |
6 | 10455413502055002 |
7 | 451036616206211 |
oct | 56575420432412 |
9 | 12332460283332 |
10 | 3212304332042 |
11 | 1029370061733 |
12 | 43a69627a462 |
13 | 1a3bc406a410 |
14 | b16951b6078 |
15 | 5885d001262 |
hex | 2ebec42350a |
3212304332042 has 16 divisors (see below), whose sum is σ = 5368041723240. Its totient is φ = 1431477792192.
The previous prime is 3212304332011. The next prime is 3212304332057. The reversal of 3212304332042 is 2402334032123.
It can be written as a sum of positive squares in 4 ways, for example, as 2642806200241 + 569498131801 = 1625671^2 + 754651^2 .
It is a super-3 number, since 3×32123043320423 (a number of 38 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (29).
It is a junction number, because it is equal to n+sod(n) for n = 3212304331996 and 3212304332014.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2130174533 + ... + 2130176040.
Almost surely, 23212304332042 is an apocalyptic number.
3212304332042 is a deficient number, since it is larger than the sum of its proper divisors (2155737391198).
3212304332042 is a wasteful number, since it uses less digits than its factorization.
3212304332042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4260350617.
The product of its (nonzero) digits is 20736, while the sum is 29.
Adding to 3212304332042 its reverse (2402334032123), we get a palindrome (5614638364165).
The spelling of 3212304332042 in words is "three trillion, two hundred twelve billion, three hundred four million, three hundred thirty-two thousand, forty-two".
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