Base | Representation |
---|---|
bin | 101110101111101100101… |
… | …110010100000111101011 |
3 | 102101002112120000011211001 |
4 | 232233230232110013223 |
5 | 410112303401242443 |
6 | 10455414341215431 |
7 | 451040042422621 |
oct | 56575456240753 |
9 | 12332476004731 |
10 | 3212312134123 |
11 | 1029374500534 |
12 | 43a698a01577 |
13 | 1a3bc586c731 |
14 | b1696247511 |
15 | 5885da42d4d |
hex | 2ebecb941eb |
3212312134123 has 2 divisors, whose sum is σ = 3212312134124. Its totient is φ = 3212312134122.
The previous prime is 3212312134043. The next prime is 3212312134147. The reversal of 3212312134123 is 3214312132123.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3212312134123 - 217 = 3212312003051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3212312134091 and 3212312134100.
It is not a weakly prime, because it can be changed into another prime (3212312134183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1606156067061 + 1606156067062.
It is an arithmetic number, because the mean of its divisors is an integer number (1606156067062).
Almost surely, 23212312134123 is an apocalyptic number.
3212312134123 is a deficient number, since it is larger than the sum of its proper divisors (1).
3212312134123 is an equidigital number, since it uses as much as digits as its factorization.
3212312134123 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5184, while the sum is 28.
Adding to 3212312134123 its reverse (3214312132123), we get a palindrome (6426624266246).
The spelling of 3212312134123 in words is "three trillion, two hundred twelve billion, three hundred twelve million, one hundred thirty-four thousand, one hundred twenty-three".
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