Search a number
-
+
321233301201193 is a prime number
BaseRepresentation
bin100100100001010001111010…
…0110011101110000100101001
31120010101121022002012111120021
41021002203310303232010221
5314101041300101414233
63055112312531200441
7124443224443661113
oct11102436463560451
91503347262174507
10321233301201193
119339a306aa1a27
12300411ba746121
1310a3222a27b614
145947abbc363b3
152721036c47e2d
hex12428f4cee129

321233301201193 has 2 divisors, whose sum is σ = 321233301201194. Its totient is φ = 321233301201192.

The previous prime is 321233301201139. The next prime is 321233301201229. The reversal of 321233301201193 is 391102103332123.

Together with previous prime (321233301201139) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 314267518118464 + 6965783082729 = 17727592^2 + 2639277^2 .

It is a cyclic number.

It is not a de Polignac number, because 321233301201193 - 233 = 321224711266601 is a prime.

It is not a weakly prime, because it can be changed into another prime (321233301201893) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160616650600596 + 160616650600597.

It is an arithmetic number, because the mean of its divisors is an integer number (160616650600597).

Almost surely, 2321233301201193 is an apocalyptic number.

It is an amenable number.

321233301201193 is a deficient number, since it is larger than the sum of its proper divisors (1).

321233301201193 is an equidigital number, since it uses as much as digits as its factorization.

321233301201193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17496, while the sum is 34.

The spelling of 321233301201193 in words is "three hundred twenty-one trillion, two hundred thirty-three billion, three hundred one million, two hundred one thousand, one hundred ninety-three".