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321243340441 = 674794676723
BaseRepresentation
bin1001010110010111001…
…10000101111010011001
31010201012000000112102211
410223023212011322121
520230401243343231
6403324355355121
732131465224442
oct4531346057231
91121160015384
10321243340441
11114269544401
12523138b2aa1
13243a6c93b3a
14117965da2c9
158552676eb1
hex4acb985e99

321243340441 has 4 divisors (see below), whose sum is σ = 326038017232. Its totient is φ = 316448663652.

The previous prime is 321243340423. The next prime is 321243340489. The reversal of 321243340441 is 144043342123.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 321243340441 - 221 = 321241243289 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (321243340841) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2397338295 + ... + 2397338428.

It is an arithmetic number, because the mean of its divisors is an integer number (81509504308).

Almost surely, 2321243340441 is an apocalyptic number.

It is an amenable number.

321243340441 is a deficient number, since it is larger than the sum of its proper divisors (4794676791).

321243340441 is an equidigital number, since it uses as much as digits as its factorization.

321243340441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4794676790.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 321243340441 its reverse (144043342123), we get a palindrome (465286682564).

The spelling of 321243340441 in words is "three hundred twenty-one billion, two hundred forty-three million, three hundred forty thousand, four hundred forty-one".

Divisors: 1 67 4794676723 321243340441