Base | Representation |
---|---|
bin | 101110101111111010100… |
… | …000010101010101100001 |
3 | 102101010010200002011112020 |
4 | 232233322200111111201 |
5 | 410113242044200423 |
6 | 10455453321052053 |
7 | 451045550631666 |
oct | 56577240252541 |
9 | 12333120064466 |
10 | 3212543350113 |
11 | 1029482a74529 |
12 | 43a742327029 |
13 | 1a3c31736326 |
14 | b16b8c33a6d |
15 | 58873eb64e3 |
hex | 2ebfa815561 |
3212543350113 has 32 divisors (see below), whose sum is σ = 4605187571712. Its totient is φ = 1986801854400.
The previous prime is 3212543350109. The next prime is 3212543350147. The reversal of 3212543350113 is 3110533452123.
It is not a de Polignac number, because 3212543350113 - 22 = 3212543350109 is a prime.
It is a super-3 number, since 3×32125433501133 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (3212543350103) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1229073 + ... + 2817038.
It is an arithmetic number, because the mean of its divisors is an integer number (143912111616).
Almost surely, 23212543350113 is an apocalyptic number.
It is an amenable number.
3212543350113 is a deficient number, since it is larger than the sum of its proper divisors (1392644221599).
3212543350113 is a wasteful number, since it uses less digits than its factorization.
3212543350113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4046485.
The product of its (nonzero) digits is 32400, while the sum is 33.
The spelling of 3212543350113 in words is "three trillion, two hundred twelve billion, five hundred forty-three million, three hundred fifty thousand, one hundred thirteen".
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