32125661004113 has 4 divisors (see below), whose sum is σ = 32125981505520. Its totient is φ = 32125340502708.

The previous prime is 32125661004109. The next prime is 32125661004139. The reversal of 32125661004113 is 31140016652123.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 32125661004113 - 2² = 32125661004109 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (32125661004313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160100303 + ... + 160300836.

It is an arithmetic number, because the mean of its divisors is an integer number (8031495376380).

Almost surely, 2^{32125661004113} is an apocalyptic number.

It is an amenable number.

32125661004113 is a deficient number, since it is larger than the sum of its proper divisors (320501407).

32125661004113 is a wasteful number, since it uses less digits than its factorization.

32125661004113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 320501406.

The product of its (nonzero) digits is 25920, while the sum is 35.

Adding to 32125661004113 its reverse (31140016652123), we get a palindrome (63265677656236).

The spelling of 32125661004113 in words is "thirty-two trillion, one hundred twenty-five billion, six hundred sixty-one million, four thousand, one hundred thirteen".