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32130000101131 is a prime number
BaseRepresentation
bin1110100111000110110010…
…01111100001111100001011
311012202121010221122222210121
413103203121033201330023
513202404220011214011
6152200152425324111
76524213232462412
oct723433117417413
9135677127588717
1032130000101131
11a26829047aa49
12372b014036637
1314c0acc8b218a
147d1159330479
153aab95b39e71
hex1d38d93e1f0b

32130000101131 has 2 divisors, whose sum is σ = 32130000101132. Its totient is φ = 32130000101130.

The previous prime is 32130000101083. The next prime is 32130000101137. The reversal of 32130000101131 is 13110100003123.

It is a strong prime.

It is an emirp because it is prime and its reverse (13110100003123) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 32130000101131 - 223 = 32129991712523 is a prime.

It is a super-2 number, since 2×321300001011312 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (32130000101137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16065000050565 + 16065000050566.

It is an arithmetic number, because the mean of its divisors is an integer number (16065000050566).

Almost surely, 232130000101131 is an apocalyptic number.

32130000101131 is a deficient number, since it is larger than the sum of its proper divisors (1).

32130000101131 is an equidigital number, since it uses as much as digits as its factorization.

32130000101131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 32130000101131 its reverse (13110100003123), we get a palindrome (45240100104254).

The spelling of 32130000101131 in words is "thirty-two trillion, one hundred thirty billion, one hundred one thousand, one hundred thirty-one".