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32130420143131 is a prime number
BaseRepresentation
bin1110100111000111100100…
…10001110111010000011011
311012202122020020001100002201
413103203302101313100123
513202411100024040011
6152200302232311031
76524226522666562
oct723436221672033
9135678206040081
1032130420143131
11a2684865947a2
12372b110842477
1314c0b6892003b
147d1199030bd9
153aabbc95bcc1
hex1d38f247741b

32130420143131 has 2 divisors, whose sum is σ = 32130420143132. Its totient is φ = 32130420143130.

The previous prime is 32130420143053. The next prime is 32130420143141. The reversal of 32130420143131 is 13134102403123.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 32130420143131 - 229 = 32129883272219 is a prime.

It is a super-2 number, since 2×321304201431312 (a number of 28 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 32130420143131.

It is not a weakly prime, because it can be changed into another prime (32130420143141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16065210071565 + 16065210071566.

It is an arithmetic number, because the mean of its divisors is an integer number (16065210071566).

Almost surely, 232130420143131 is an apocalyptic number.

32130420143131 is a deficient number, since it is larger than the sum of its proper divisors (1).

32130420143131 is an equidigital number, since it uses as much as digits as its factorization.

32130420143131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 32130420143131 its reverse (13134102403123), we get a palindrome (45264522546254).

The spelling of 32130420143131 in words is "thirty-two trillion, one hundred thirty billion, four hundred twenty million, one hundred forty-three thousand, one hundred thirty-one".