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321312300110041 is a prime number
BaseRepresentation
bin100100100001110110101100…
…1100000101001000011011001
31120010200011012122120212200011
41021003231121200221003121
5314103340042312010131
63055212455524041521
7124452022221425452
oct11103553140510331
91503604178525604
10321312300110041
119341a8658aa449
12300545872332a1
1310a39809b836b6
14594b853a5c129
15272310c3bc0b1
hex1243b598290d9

321312300110041 has 2 divisors, whose sum is σ = 321312300110042. Its totient is φ = 321312300110040.

The previous prime is 321312300109987. The next prime is 321312300110159. The reversal of 321312300110041 is 140011003213123.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 319612872398400 + 1699427711641 = 17877720^2 + 1303621^2 .

It is a cyclic number.

It is not a de Polignac number, because 321312300110041 - 245 = 286127928021209 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 321312300109994 and 321312300110021.

It is not a weakly prime, because it can be changed into another prime (321312300113041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160656150055020 + 160656150055021.

It is an arithmetic number, because the mean of its divisors is an integer number (160656150055021).

Almost surely, 2321312300110041 is an apocalyptic number.

It is an amenable number.

321312300110041 is a deficient number, since it is larger than the sum of its proper divisors (1).

321312300110041 is an equidigital number, since it uses as much as digits as its factorization.

321312300110041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 321312300110041 its reverse (140011003213123), we get a palindrome (461323303323164).

The spelling of 321312300110041 in words is "three hundred twenty-one trillion, three hundred twelve billion, three hundred million, one hundred ten thousand, forty-one".