Base | Representation |
---|---|
bin | 101110110000100011100… |
… | …111001001001010110001 |
3 | 102101011220201210001212202 |
4 | 232300203213021022301 |
5 | 410121200122014022 |
6 | 10500045554432545 |
7 | 451101623601245 |
oct | 56604347111261 |
9 | 12334821701782 |
10 | 3213233001137 |
11 | 10297a7295555 |
12 | 43a8b5292755 |
13 | 1a4011591063 |
14 | b1742676425 |
15 | 588b47e2592 |
hex | 2ec239c92b1 |
3213233001137 has 2 divisors, whose sum is σ = 3213233001138. Its totient is φ = 3213233001136.
The previous prime is 3213233001113. The next prime is 3213233001151. The reversal of 3213233001137 is 7311003323123.
3213233001137 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2552977622416 + 660255378721 = 1597804^2 + 812561^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3213233001137 is a prime.
It is not a weakly prime, because it can be changed into another prime (3213233001197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1606616500568 + 1606616500569.
It is an arithmetic number, because the mean of its divisors is an integer number (1606616500569).
Almost surely, 23213233001137 is an apocalyptic number.
It is an amenable number.
3213233001137 is a deficient number, since it is larger than the sum of its proper divisors (1).
3213233001137 is an equidigital number, since it uses as much as digits as its factorization.
3213233001137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 29.
The spelling of 3213233001137 in words is "three trillion, two hundred thirteen billion, two hundred thirty-three million, one thousand, one hundred thirty-seven".
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