Base | Representation |
---|---|
bin | 101110110000100100001… |
… | …001011111001001001011 |
3 | 102101011221100201110112201 |
4 | 232300210021133021023 |
5 | 410121204423112133 |
6 | 10500050515421031 |
7 | 451102063245631 |
oct | 56604411371113 |
9 | 12334840643481 |
10 | 3213242004043 |
11 | 1029801384575 |
12 | 43a8b82b4777 |
13 | 1a40133c3b16 |
14 | b174393b351 |
15 | 588b54bed7d |
hex | 2ec2425f24b |
3213242004043 has 4 divisors (see below), whose sum is σ = 3213248340600. Its totient is φ = 3213235667488.
The previous prime is 3213242004029. The next prime is 3213242004059. The reversal of 3213242004043 is 3404002423123.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3213242004043 - 213 = 3213241995851 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3213242004023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2334493 + ... + 3446206.
It is an arithmetic number, because the mean of its divisors is an integer number (803312085150).
Almost surely, 23213242004043 is an apocalyptic number.
3213242004043 is a deficient number, since it is larger than the sum of its proper divisors (6336557).
3213242004043 is an equidigital number, since it uses as much as digits as its factorization.
3213242004043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6336556.
The product of its (nonzero) digits is 13824, while the sum is 28.
Adding to 3213242004043 its reverse (3404002423123), we get a palindrome (6617244427166).
The spelling of 3213242004043 in words is "three trillion, two hundred thirteen billion, two hundred forty-two million, four thousand, forty-three".
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