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3213404141011 = 16991891350289
BaseRepresentation
bin101110110000101101110…
…011111111010111010011
3102101012100122210212122121
4232300231303333113103
5410122022430003021
610500114550515111
7451106102345311
oct56605563772723
912335318725577
103213404141011
111029884956469
1243a942665a97
131a403ab8215c
14b175b2a50b1
15588c484a741
hex2ec2dcff5d3

3213404141011 has 4 divisors (see below), whose sum is σ = 3215295493000. Its totient is φ = 3211512789024.

The previous prime is 3213404141009. The next prime is 3213404141039. The reversal of 3213404141011 is 1101414043123.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3213404141011 - 21 = 3213404141009 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3213404141081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 945673446 + ... + 945676843.

It is an arithmetic number, because the mean of its divisors is an integer number (803823873250).

Almost surely, 23213404141011 is an apocalyptic number.

3213404141011 is a deficient number, since it is larger than the sum of its proper divisors (1891351989).

3213404141011 is a wasteful number, since it uses less digits than its factorization.

3213404141011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1891351988.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 3213404141011 its reverse (1101414043123), we get a palindrome (4314818184134).

The spelling of 3213404141011 in words is "three trillion, two hundred thirteen billion, four hundred four million, one hundred forty-one thousand, eleven".

Divisors: 1 1699 1891350289 3213404141011