Base | Representation |
---|---|
bin | 1011111110001001… |
… | …0001110100000001 |
3 | 22021221122100220021 |
4 | 2333202101310001 |
5 | 23040114342423 |
6 | 1250511013441 |
7 | 142426511401 |
oct | 27742216401 |
9 | 8257570807 |
10 | 3213434113 |
11 | 13a999967a |
12 | 75820a281 |
13 | 3c2993506 |
14 | 226ac4801 |
15 | 13c1a395d |
hex | bf891d01 |
3213434113 has 4 divisors (see below), whose sum is σ = 3213583108. Its totient is φ = 3213285120.
The previous prime is 3213434093. The next prime is 3213434131. The reversal of 3213434113 is 3114343123.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1779827344 + 1433606769 = 42188^2 + 37863^2 .
It is a cyclic number.
It is not a de Polignac number, because 3213434113 - 213 = 3213425921 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3213434143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35256 + ... + 87577.
It is an arithmetic number, because the mean of its divisors is an integer number (803395777).
Almost surely, 23213434113 is an apocalyptic number.
It is an amenable number.
3213434113 is a deficient number, since it is larger than the sum of its proper divisors (148995).
3213434113 is a wasteful number, since it uses less digits than its factorization.
3213434113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 148994.
The product of its digits is 2592, while the sum is 25.
The square root of 3213434113 is about 56687.1600364668. The cubic root of 3213434113 is about 1475.6718743939.
Adding to 3213434113 its reverse (3114343123), we get a palindrome (6327777236).
The spelling of 3213434113 in words is "three billion, two hundred thirteen million, four hundred thirty-four thousand, one hundred thirteen".
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