Base | Representation |
---|---|
bin | 101110110000110011110… |
… | …100011011111100011011 |
3 | 102101012121200110001022112 |
4 | 232300303310123330123 |
5 | 410122224224440441 |
6 | 10500132550542535 |
7 | 451111435100513 |
oct | 56606364337433 |
9 | 12335550401275 |
10 | 3213504921371 |
11 | 1029926830218 |
12 | 43a970367a4b |
13 | 1a4055a09bc4 |
14 | b176a81a843 |
15 | 588cd6064eb |
hex | 2ec33d1bf1b |
3213504921371 has 16 divisors (see below), whose sum is σ = 3355887034368. Its totient is φ = 3071345877600.
The previous prime is 3213504921349. The next prime is 3213504921377. The reversal of 3213504921371 is 1731294053123.
It is a cyclic number.
It is not a de Polignac number, because 3213504921371 - 218 = 3213504659227 is a prime.
It is a super-2 number, since 2×32135049213712 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3213504921377) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 184347026 + ... + 184364456.
It is an arithmetic number, because the mean of its divisors is an integer number (209742939648).
Almost surely, 23213504921371 is an apocalyptic number.
3213504921371 is a deficient number, since it is larger than the sum of its proper divisors (142382112997).
3213504921371 is a wasteful number, since it uses less digits than its factorization.
3213504921371 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23362.
The product of its (nonzero) digits is 136080, while the sum is 41.
Adding to 3213504921371 its reverse (1731294053123), we get a palindrome (4944798974494).
The spelling of 3213504921371 in words is "three trillion, two hundred thirteen billion, five hundred four million, nine hundred twenty-one thousand, three hundred seventy-one".
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