Base | Representation |
---|---|
bin | 101110110001010010000… |
… | …011100011100111100001 |
3 | 102101020221000222112202021 |
4 | 232301102003203213201 |
5 | 410124244110421231 |
6 | 10500255151421441 |
7 | 451130134645246 |
oct | 56612203434741 |
9 | 12336830875667 |
10 | 3214012201441 |
11 | 102a06710a248 |
12 | 43aa92224881 |
13 | 1a4106b40822 |
14 | b17b7d495cd |
15 | 5890ce0b811 |
hex | 2ec520e39e1 |
3214012201441 has 2 divisors, whose sum is σ = 3214012201442. Its totient is φ = 3214012201440.
The previous prime is 3214012201429. The next prime is 3214012201447. The reversal of 3214012201441 is 1441022104123.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2340581770816 + 873430430625 = 1529896^2 + 934575^2 .
It is a cyclic number.
It is not a de Polignac number, because 3214012201441 - 215 = 3214012168673 is a prime.
It is not a weakly prime, because it can be changed into another prime (3214012201447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1607006100720 + 1607006100721.
It is an arithmetic number, because the mean of its divisors is an integer number (1607006100721).
Almost surely, 23214012201441 is an apocalyptic number.
It is an amenable number.
3214012201441 is a deficient number, since it is larger than the sum of its proper divisors (1).
3214012201441 is an equidigital number, since it uses as much as digits as its factorization.
3214012201441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 3214012201441 its reverse (1441022104123), we get a palindrome (4655034305564).
The spelling of 3214012201441 in words is "three trillion, two hundred fourteen billion, twelve million, two hundred one thousand, four hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •