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3214012201441 is a prime number
BaseRepresentation
bin101110110001010010000…
…011100011100111100001
3102101020221000222112202021
4232301102003203213201
5410124244110421231
610500255151421441
7451130134645246
oct56612203434741
912336830875667
103214012201441
11102a06710a248
1243aa92224881
131a4106b40822
14b17b7d495cd
155890ce0b811
hex2ec520e39e1

3214012201441 has 2 divisors, whose sum is σ = 3214012201442. Its totient is φ = 3214012201440.

The previous prime is 3214012201429. The next prime is 3214012201447. The reversal of 3214012201441 is 1441022104123.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2340581770816 + 873430430625 = 1529896^2 + 934575^2 .

It is a cyclic number.

It is not a de Polignac number, because 3214012201441 - 215 = 3214012168673 is a prime.

It is not a weakly prime, because it can be changed into another prime (3214012201447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1607006100720 + 1607006100721.

It is an arithmetic number, because the mean of its divisors is an integer number (1607006100721).

Almost surely, 23214012201441 is an apocalyptic number.

It is an amenable number.

3214012201441 is a deficient number, since it is larger than the sum of its proper divisors (1).

3214012201441 is an equidigital number, since it uses as much as digits as its factorization.

3214012201441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 3214012201441 its reverse (1441022104123), we get a palindrome (4655034305564).

The spelling of 3214012201441 in words is "three trillion, two hundred fourteen billion, twelve million, two hundred one thousand, four hundred forty-one".