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3214031345153 is a prime number
BaseRepresentation
bin101110110001010011001…
…100100101011000000001
3102101020222101000010222122
4232301103030211120001
5410124314011021103
610500301114014025
7451130456446646
oct56612314453001
912336871003878
103214031345153
11102a0769a51a2
1243aa98717315
131a410aab4275
14b17ba6cddcd
155890e93db38
hex2ec53325601

3214031345153 has 2 divisors, whose sum is σ = 3214031345154. Its totient is φ = 3214031345152.

The previous prime is 3214031345123. The next prime is 3214031345249. The reversal of 3214031345153 is 3515431304123.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2213855337409 + 1000176007744 = 1487903^2 + 1000088^2 .

It is a cyclic number.

It is not a de Polignac number, because 3214031345153 - 28 = 3214031344897 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (3214031345113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1607015672576 + 1607015672577.

It is an arithmetic number, because the mean of its divisors is an integer number (1607015672577).

Almost surely, 23214031345153 is an apocalyptic number.

It is an amenable number.

3214031345153 is a deficient number, since it is larger than the sum of its proper divisors (1).

3214031345153 is an equidigital number, since it uses as much as digits as its factorization.

3214031345153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64800, while the sum is 35.

Adding to 3214031345153 its reverse (3515431304123), we get a palindrome (6729462649276).

The spelling of 3214031345153 in words is "three trillion, two hundred fourteen billion, thirty-one million, three hundred forty-five thousand, one hundred fifty-three".