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32140433224114 = 216070216612057
BaseRepresentation
bin1110100111011010001110…
…00110101111000110110010
311012210121002001102112221221
413103231013012233012302
513203042101401132424
6152205040003335254
76525032616532525
oct723550706570662
9135717061375857
1032140433224114
11a271754723736
12373104608152a
1314c1aa323a527
147d1868bdabbc
153ab0a6a509e4
hex1d3b471af1b2

32140433224114 has 4 divisors (see below), whose sum is σ = 48210649836174. Its totient is φ = 16070216612056.

The previous prime is 32140433224111. The next prime is 32140433224297. The reversal of 32140433224114 is 41142233404123.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 19984520864025 + 12155912360089 = 4470405^2 + 3486533^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 32140433224114.

It is not an unprimeable number, because it can be changed into a prime (32140433224111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8035108306027 + ... + 8035108306030.

Almost surely, 232140433224114 is an apocalyptic number.

32140433224114 is a deficient number, since it is larger than the sum of its proper divisors (16070216612060).

32140433224114 is a wasteful number, since it uses less digits than its factorization.

32140433224114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16070216612059.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 32140433224114 its reverse (41142233404123), we get a palindrome (73282666628237).

The spelling of 32140433224114 in words is "thirty-two trillion, one hundred forty billion, four hundred thirty-three million, two hundred twenty-four thousand, one hundred fourteen".

Divisors: 1 2 16070216612057 32140433224114