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32140440433 = 103312043111
BaseRepresentation
bin11101111011101110…
…000011001101110001
310001221220220112122201
4131323232003031301
51011310423043213
622433133103201
72215320143653
oct357356031561
9101856815581
1032140440433
11126a3493672
12628b927b01
1330529720ba
1417ac8206d3
15c819cd6dd
hex77bb83371

32140440433 has 4 divisors (see below), whose sum is σ = 32452483648. Its totient is φ = 31828397220.

The previous prime is 32140440403. The next prime is 32140440439. The reversal of 32140440433 is 33404404123.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33404404123 = 281118876883.

It is a cyclic number.

It is not a de Polignac number, because 32140440433 - 25 = 32140440401 is a prime.

It is a super-2 number, since 2×321404404332 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (32140440439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 156021453 + ... + 156021658.

It is an arithmetic number, because the mean of its divisors is an integer number (8113120912).

Almost surely, 232140440433 is an apocalyptic number.

It is an amenable number.

32140440433 is a deficient number, since it is larger than the sum of its proper divisors (312043215).

32140440433 is a wasteful number, since it uses less digits than its factorization.

32140440433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 312043214.

The product of its (nonzero) digits is 13824, while the sum is 28.

Adding to 32140440433 its reverse (33404404123), we get a palindrome (65544844556).

The spelling of 32140440433 in words is "thirty-two billion, one hundred forty million, four hundred forty thousand, four hundred thirty-three".

Divisors: 1 103 312043111 32140440433