Base | Representation |
---|---|
bin | 100100100010101101100011… |
… | …1100111000110010010011011 |
3 | 1120011002102022010100011211011 |
4 | 1021011123013213012102123 |
5 | 314112302332010212103 |
6 | 3055342542113114351 |
7 | 124463362543120216 |
oct | 11105330747062233 |
9 | 1504072263304734 |
10 | 321430111413403 |
11 | 93465821255373 |
12 | 30073385b589b7 |
13 | 10a479637962a5 |
14 | 595342c42a77d |
15 | 2726205139d6d |
hex | 12456c79c649b |
321430111413403 has 2 divisors, whose sum is σ = 321430111413404. Its totient is φ = 321430111413402.
The previous prime is 321430111413391. The next prime is 321430111413409. The reversal of 321430111413403 is 304314111034123.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-321430111413403 is a prime.
It is not a weakly prime, because it can be changed into another prime (321430111413409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160715055706701 + 160715055706702.
It is an arithmetic number, because the mean of its divisors is an integer number (160715055706702).
Almost surely, 2321430111413403 is an apocalyptic number.
321430111413403 is a deficient number, since it is larger than the sum of its proper divisors (1).
321430111413403 is an equidigital number, since it uses as much as digits as its factorization.
321430111413403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 321430111413403 its reverse (304314111034123), we get a palindrome (625744222447526).
The spelling of 321430111413403 in words is "three hundred twenty-one trillion, four hundred thirty billion, one hundred eleven million, four hundred thirteen thousand, four hundred three".
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