Base | Representation |
---|---|
bin | 1011111110010110… |
… | …0111101011110011 |
3 | 22022000021212120101 |
4 | 2333211213223303 |
5 | 23040330411011 |
6 | 1250541453231 |
7 | 142440120364 |
oct | 27745475363 |
9 | 8260255511 |
10 | 3214310131 |
11 | 13aa43785a |
12 | 758571217 |
13 | 3c2c0c176 |
14 | 226c71b6b |
15 | 13c2c82c1 |
hex | bf967af3 |
3214310131 has 2 divisors, whose sum is σ = 3214310132. Its totient is φ = 3214310130.
The previous prime is 3214310107. The next prime is 3214310171. The reversal of 3214310131 is 1310134123.
It is a weak prime.
It is an emirp because it is prime and its reverse (1310134123) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3214310131 - 29 = 3214309619 is a prime.
It is a super-2 number, since 2×32143101312 = 20663579236498474322, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3214310099 and 3214310108.
It is not a weakly prime, because it can be changed into another prime (3214310171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1607155065 + 1607155066.
It is an arithmetic number, because the mean of its divisors is an integer number (1607155066).
Almost surely, 23214310131 is an apocalyptic number.
3214310131 is a deficient number, since it is larger than the sum of its proper divisors (1).
3214310131 is an equidigital number, since it uses as much as digits as its factorization.
3214310131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
The square root of 3214310131 is about 56694.8862861546. The cubic root of 3214310131 is about 1475.8059570841.
Adding to 3214310131 its reverse (1310134123), we get a palindrome (4524444254).
The spelling of 3214310131 in words is "three billion, two hundred fourteen million, three hundred ten thousand, one hundred thirty-one".
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