Base | Representation |
---|---|
bin | 101110110100001100011… |
… | …111000000111000000001 |
3 | 102101120000000102012201200 |
4 | 232310030133000320001 |
5 | 410202200312230340 |
6 | 10501533402251413 |
7 | 451300504321632 |
oct | 56641437007001 |
9 | 12346000365650 |
10 | 3217139961345 |
11 | 1030421701592 |
12 | 43b6057b6b69 |
13 | 1a44b4b3802b |
14 | b19d34cb889 |
15 | 58a427da330 |
hex | 2ed0c7c0e01 |
3217139961345 has 48 divisors (see below), whose sum is σ = 5824158275520. Its totient is φ = 1641139235712.
The previous prime is 3217139961337. The next prime is 3217139961349. The reversal of 3217139961345 is 5431699317123.
3217139961345 is a `hidden beast` number, since 3 + 2 + 1 + 7 + 13 + 9 + 9 + 613 + 4 + 5 = 666.
It is not a de Polignac number, because 3217139961345 - 23 = 3217139961337 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3217139961291 and 3217139961300.
It is not an unprimeable number, because it can be changed into a prime (3217139961349) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 16276479 + ... + 16472948.
It is an arithmetic number, because the mean of its divisors is an integer number (121336630740).
Almost surely, 23217139961345 is an apocalyptic number.
It is an amenable number.
3217139961345 is a deficient number, since it is larger than the sum of its proper divisors (2607018314175).
3217139961345 is a wasteful number, since it uses less digits than its factorization.
3217139961345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32749534 (or 32749531 counting only the distinct ones).
The product of its digits is 3674160, while the sum is 54.
The spelling of 3217139961345 in words is "three trillion, two hundred seventeen billion, one hundred thirty-nine million, nine hundred sixty-one thousand, three hundred forty-five".
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