Base | Representation |
---|---|
bin | 1001010111110010111… |
… | …10111000101010110001 |
3 | 1010210011122122121111102 |
4 | 10223321132320222301 |
5 | 20233440334444441 |
6 | 403533020254145 |
7 | 32156534031161 |
oct | 4537136705261 |
9 | 1123148577442 |
10 | 322013203121 |
11 | 114624070655 |
12 | 524a96a1355 |
13 | 2449a62439c |
14 | 1182a95c5a1 |
15 | 859a04969b |
hex | 4af97b8ab1 |
322013203121 has 2 divisors, whose sum is σ = 322013203122. Its totient is φ = 322013203120.
The previous prime is 322013203097. The next prime is 322013203133. The reversal of 322013203121 is 121302310223.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 165596908096 + 156416295025 = 406936^2 + 395495^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-322013203121 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 322013203093 and 322013203102.
It is not a weakly prime, because it can be changed into another prime (322013403121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161006601560 + 161006601561.
It is an arithmetic number, because the mean of its divisors is an integer number (161006601561).
Almost surely, 2322013203121 is an apocalyptic number.
It is an amenable number.
322013203121 is a deficient number, since it is larger than the sum of its proper divisors (1).
322013203121 is an equidigital number, since it uses as much as digits as its factorization.
322013203121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 322013203121 its reverse (121302310223), we get a palindrome (443315513344).
The spelling of 322013203121 in words is "three hundred twenty-two billion, thirteen million, two hundred three thousand, one hundred twenty-one".
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