Base | Representation |
---|---|
bin | 101110110111000000001… |
… | …101110100111110101011 |
3 | 102101211210011102002021001 |
4 | 232313000031310332223 |
5 | 410224334232330201 |
6 | 10503152520455431 |
7 | 451435310620135 |
oct | 56670015647653 |
9 | 12354704362231 |
10 | 3220155355051 |
11 | 10317298264a8 |
12 | 44010761a577 |
13 | 1a487577c16b |
14 | b1bdbb80055 |
15 | 58b6c3c0301 |
hex | 2edc0374fab |
3220155355051 has 4 divisors (see below), whose sum is σ = 3220159165600. Its totient is φ = 3220151544504.
The previous prime is 3220155354979. The next prime is 3220155355147. The reversal of 3220155355051 is 1505535510223.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 3220155355051 - 211 = 3220155353003 is a prime.
It is a super-3 number, since 3×32201553550513 (a number of 39 digits) contains 333 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 3220155355051.
It is not an unprimeable number, because it can be changed into a prime (3220156355051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7731 + ... + 2537788.
It is an arithmetic number, because the mean of its divisors is an integer number (805039791400).
Almost surely, 23220155355051 is an apocalyptic number.
3220155355051 is a deficient number, since it is larger than the sum of its proper divisors (3810549).
3220155355051 is a wasteful number, since it uses less digits than its factorization.
3220155355051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3810548.
The product of its (nonzero) digits is 112500, while the sum is 37.
The spelling of 3220155355051 in words is "three trillion, two hundred twenty billion, one hundred fifty-five million, three hundred fifty-five thousand, fifty-one".
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