Base | Representation |
---|---|
bin | 101110111000110101111… |
… | …110011011100001100001 |
3 | 102102000212211222202221111 |
4 | 232320311332123201201 |
5 | 410242411020430423 |
6 | 10504120534223321 |
7 | 451535260600552 |
oct | 56706576334141 |
9 | 12360784882844 |
10 | 3222131030113 |
11 | 1032552a69406 |
12 | 4405791b4b41 |
13 | 1a4acbb8a668 |
14 | b1d48306329 |
15 | 58c35a7a60d |
hex | 2ee35f9b861 |
3222131030113 has 2 divisors, whose sum is σ = 3222131030114. Its totient is φ = 3222131030112.
The previous prime is 3222131030051. The next prime is 3222131030143. The reversal of 3222131030113 is 3110301312223.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3124066855009 + 98064175104 = 1767503^2 + 313152^2 .
It is a cyclic number.
It is not a de Polignac number, because 3222131030113 - 221 = 3222128932961 is a prime.
It is not a weakly prime, because it can be changed into another prime (3222131030143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1611065515056 + 1611065515057.
It is an arithmetic number, because the mean of its divisors is an integer number (1611065515057).
Almost surely, 23222131030113 is an apocalyptic number.
It is an amenable number.
3222131030113 is a deficient number, since it is larger than the sum of its proper divisors (1).
3222131030113 is an equidigital number, since it uses as much as digits as its factorization.
3222131030113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 3222131030113 its reverse (3110301312223), we get a palindrome (6332432342336).
The spelling of 3222131030113 in words is "three trillion, two hundred twenty-two billion, one hundred thirty-one million, thirty thousand, one hundred thirteen".
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