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32231300132081 is a prime number
BaseRepresentation
bin1110101010000011011110…
…01100011110110011110001
311020010021121201112202020202
413111001233030132303301
513211034200313211311
6152314504352444545
76534430443520541
oct725015714366361
9136107551482222
1032231300132081
11a2a7243724596
123746785249755
1314ca52483a9ab
147d6008cbd321
153ad62406de3b
hex1d506f31ecf1

32231300132081 has 2 divisors, whose sum is σ = 32231300132082. Its totient is φ = 32231300132080.

The previous prime is 32231300132047. The next prime is 32231300132113. The reversal of 32231300132081 is 18023100313223.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 27769738090000 + 4461562042081 = 5269700^2 + 2112241^2 .

It is an emirp because it is prime and its reverse (18023100313223) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-32231300132081 is a prime.

It is a super-2 number, since 2×322313001320812 (a number of 28 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (32231300132011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16115650066040 + 16115650066041.

It is an arithmetic number, because the mean of its divisors is an integer number (16115650066041).

Almost surely, 232231300132081 is an apocalyptic number.

It is an amenable number.

32231300132081 is a deficient number, since it is larger than the sum of its proper divisors (1).

32231300132081 is an equidigital number, since it uses as much as digits as its factorization.

32231300132081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 29.

The spelling of 32231300132081 in words is "thirty-two trillion, two hundred thirty-one billion, three hundred million, one hundred thirty-two thousand, eighty-one".