3224113144033 has 4 divisors (see below), whose sum is σ = 3224331313840. Its totient is φ = 3223894974228.

The previous prime is 3224113143989. The next prime is 3224113144051. The reversal of 3224113144033 is 3304413114223.

3224113144033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3224113144033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3224113143986 and 3224113144004.

It is not an unprimeable number, because it can be changed into a prime (3224113144333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 109062735 + ... + 109092292.

It is an arithmetic number, because the mean of its divisors is an integer number (806082828460).

Almost surely, 2^{3224113144033} is an apocalyptic number.

It is an amenable number.

3224113144033 is a deficient number, since it is larger than the sum of its proper divisors (218169807).

3224113144033 is a wasteful number, since it uses less digits than its factorization.

3224113144033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 218169806.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 3224113144033 its reverse (3304413114223), we get a palindrome (6528526258256).

The spelling of 3224113144033 in words is "three trillion, two hundred twenty-four billion, one hundred thirteen million, one hundred forty-four thousand, thirty-three".