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3225140544553 = 19607927923053
BaseRepresentation
bin101110111011101001010…
…110110100010000101001
3102102022122120220221122021
4232323221112310100221
5410320041434411203
610505335322424441
7452002663211254
oct56735126642051
912368576827567
103225140544553
111033857838124
12441079062121
131a518b523735
14b2151ca809b
1558d5ed9d5bd
hex2eee95b4429

3225140544553 has 8 divisors (see below), whose sum is σ = 3395443366400. Its totient is φ = 3054893581008.

The previous prime is 3225140544539. The next prime is 3225140544569. The reversal of 3225140544553 is 3554450415223.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3225140544553 - 213 = 3225140536361 is a prime.

It is not an unprimeable number, because it can be changed into a prime (3225140544533) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13846026 + ... + 14077027.

It is an arithmetic number, because the mean of its divisors is an integer number (424430420800).

Almost surely, 23225140544553 is an apocalyptic number.

It is an amenable number.

3225140544553 is a deficient number, since it is larger than the sum of its proper divisors (170302821847).

3225140544553 is a wasteful number, since it uses less digits than its factorization.

3225140544553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27929151.

The product of its (nonzero) digits is 1440000, while the sum is 43.

Adding to 3225140544553 its reverse (3554450415223), we get a palindrome (6779590959776).

The spelling of 3225140544553 in words is "three trillion, two hundred twenty-five billion, one hundred forty million, five hundred forty-four thousand, five hundred fifty-three".

Divisors: 1 19 6079 115501 27923053 530538007 169744239187 3225140544553