Base | Representation |
---|---|
bin | 101111000000001100111… |
… | …110011111000000101011 |
3 | 102102210021120011011222220 |
4 | 233000030332133000223 |
5 | 410410101434110011 |
6 | 10511505015245123 |
7 | 452235142312506 |
oct | 57001476370053 |
9 | 12383246134886 |
10 | 3230033113131 |
11 | 1035938538330 |
12 | 4420036797a3 |
13 | 1a578b039126 |
14 | b24979a213d |
15 | 59049683506 |
hex | 2f00cf9f02b |
3230033113131 has 16 divisors (see below), whose sum is σ = 4762589301120. Its totient is φ = 1930779443520.
The previous prime is 3230033113091. The next prime is 3230033113141. The reversal of 3230033113131 is 1313113300323.
3230033113131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3230033113131 - 213 = 3230033104939 is a prime.
It is a super-2 number, since 2×32300331131312 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (3230033113141) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 670407121 + ... + 670411938.
It is an arithmetic number, because the mean of its divisors is an integer number (297661831320).
Almost surely, 23230033113131 is an apocalyptic number.
3230033113131 is a deficient number, since it is larger than the sum of its proper divisors (1532556187989).
3230033113131 is a wasteful number, since it uses less digits than its factorization.
3230033113131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1340819146.
The product of its (nonzero) digits is 1458, while the sum is 24.
Adding to 3230033113131 its reverse (1313113300323), we get a palindrome (4543146413454).
The spelling of 3230033113131 in words is "three trillion, two hundred thirty billion, thirty-three million, one hundred thirteen thousand, one hundred thirty-one".
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