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32301110113 = 191700058427
BaseRepresentation
bin11110000101010010…
…111101001101100001
310002101010020102000121
4132011102331031201
51012123041010423
622501112520241
72222310622456
oct360522751541
9102333212017
1032301110113
1112776153128
1263156b0081
13307a03860c
1417c5cc582d
15c90b6945d
hex7854bd361

32301110113 has 4 divisors (see below), whose sum is σ = 34001168560. Its totient is φ = 30601051668.

The previous prime is 32301110089. The next prime is 32301110131. The reversal of 32301110113 is 31101110323.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 32301110113 - 25 = 32301110081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (32301110143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 850029195 + ... + 850029232.

It is an arithmetic number, because the mean of its divisors is an integer number (8500292140).

Almost surely, 232301110113 is an apocalyptic number.

It is an amenable number.

32301110113 is a deficient number, since it is larger than the sum of its proper divisors (1700058447).

32301110113 is a wasteful number, since it uses less digits than its factorization.

32301110113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1700058446.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 32301110113 its reverse (31101110323), we get a palindrome (63402220436).

The spelling of 32301110113 in words is "thirty-two billion, three hundred one million, one hundred ten thousand, one hundred thirteen".

Divisors: 1 19 1700058427 32301110113