Base | Representation |
---|---|
bin | 101111000000011000010… |
… | …011101100101000001011 |
3 | 102102210202210212210010112 |
4 | 233000120103230220023 |
5 | 410410444121121212 |
6 | 10511535530104535 |
7 | 452242641236543 |
oct | 57003023545013 |
9 | 12383683783115 |
10 | 3230223223307 |
11 | 1035a25885983 |
12 | 44205727b14b |
13 | 1a57bb53ca62 |
14 | b24b4d2c323 |
15 | 5905b1d7422 |
hex | 2f0184eca0b |
3230223223307 has 2 divisors, whose sum is σ = 3230223223308. Its totient is φ = 3230223223306.
The previous prime is 3230223223273. The next prime is 3230223223313. The reversal of 3230223223307 is 7033223220323.
It is a strong prime.
It is an emirp because it is prime and its reverse (7033223220323) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3230223223307 - 220 = 3230222174731 is a prime.
It is a super-3 number, since 3×32302232233073 (a number of 39 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (3230223223207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1615111611653 + 1615111611654.
It is an arithmetic number, because the mean of its divisors is an integer number (1615111611654).
Almost surely, 23230223223307 is an apocalyptic number.
3230223223307 is a deficient number, since it is larger than the sum of its proper divisors (1).
3230223223307 is an equidigital number, since it uses as much as digits as its factorization.
3230223223307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 32.
The spelling of 3230223223307 in words is "three trillion, two hundred thirty billion, two hundred twenty-three million, two hundred twenty-three thousand, three hundred seven".
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