3230504050331 has 2 divisors, whose sum is σ = 3230504050332. Its totient is φ = 3230504050330.

The previous prime is 3230504050309. The next prime is 3230504050349. The reversal of 3230504050331 is 1330504050323.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3230504050331 is a prime.

It is a super-3 number, since 3×3230504050331³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 3230504050294 and 3230504050303.

It is not a weakly prime, because it can be changed into another prime (3230504050351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1615252025165 + 1615252025166.

It is an arithmetic number, because the mean of its divisors is an integer number (1615252025166).

Almost surely, 2^{3230504050331} is an apocalyptic number.

3230504050331 is a deficient number, since it is larger than the sum of its proper divisors (1).

3230504050331 is an equidigital number, since it uses as much as digits as its factorization.

3230504050331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16200, while the sum is 29.

The spelling of 3230504050331 in words is "three trillion, two hundred thirty billion, five hundred four million, fifty thousand, three hundred thirty-one".