Base | Representation |
---|---|
bin | 101111000001001110100… |
… | …011011010101111010001 |
3 | 102102220010020101011212021 |
4 | 233001032203122233101 |
5 | 410414330112022001 |
6 | 10512210120331441 |
7 | 452304332003305 |
oct | 57011643325721 |
9 | 12386106334767 |
10 | 3231133314001 |
11 | 103635257a54a |
12 | 442270013b81 |
13 | 1a5904c5a368 |
14 | b255db53d05 |
15 | 590b1058ba1 |
hex | 2f04e8dabd1 |
3231133314001 has 2 divisors, whose sum is σ = 3231133314002. Its totient is φ = 3231133314000.
The previous prime is 3231133313971. The next prime is 3231133314011. The reversal of 3231133314001 is 1004133311323.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2208719102976 + 1022414211025 = 1486176^2 + 1011145^2 .
It is a cyclic number.
It is not a de Polignac number, because 3231133314001 - 221 = 3231131216849 is a prime.
It is not a weakly prime, because it can be changed into another prime (3231133314011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1615566657000 + 1615566657001.
It is an arithmetic number, because the mean of its divisors is an integer number (1615566657001).
Almost surely, 23231133314001 is an apocalyptic number.
It is an amenable number.
3231133314001 is a deficient number, since it is larger than the sum of its proper divisors (1).
3231133314001 is an equidigital number, since it uses as much as digits as its factorization.
3231133314001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 3231133314001 its reverse (1004133311323), we get a palindrome (4235266625324).
The spelling of 3231133314001 in words is "three trillion, two hundred thirty-one billion, one hundred thirty-three million, three hundred fourteen thousand, one".
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