Base | Representation |
---|---|
bin | 1110101100011000101101… |
… | …01110010111001011010001 |
3 | 11020101221102102121221001121 |
4 | 13112030112232113023101 |
5 | 13213342242034020423 |
6 | 152415354520202241 |
7 | 6543265054161166 |
oct | 726142656271321 |
9 | 136357372557047 |
10 | 32311420220113 |
11 | a3282183a2581 |
12 | 375a205309381 |
13 | 1504c527ca7c8 |
14 | 7d9c4999806d |
15 | 3b0762d5e45d |
hex | 1d6316b972d1 |
32311420220113 has 2 divisors, whose sum is σ = 32311420220114. Its totient is φ = 32311420220112.
The previous prime is 32311420220083. The next prime is 32311420220291. The reversal of 32311420220113 is 31102202411323.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 31276537206849 + 1034883013264 = 5592543^2 + 1017292^2 .
It is a cyclic number.
It is not a de Polignac number, because 32311420220113 - 25 = 32311420220081 is a prime.
It is not a weakly prime, because it can be changed into another prime (32311420223113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16155710110056 + 16155710110057.
It is an arithmetic number, because the mean of its divisors is an integer number (16155710110057).
Almost surely, 232311420220113 is an apocalyptic number.
It is an amenable number.
32311420220113 is a deficient number, since it is larger than the sum of its proper divisors (1).
32311420220113 is an equidigital number, since it uses as much as digits as its factorization.
32311420220113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 32311420220113 its reverse (31102202411323), we get a palindrome (63413622631436).
The spelling of 32311420220113 in words is "thirty-two trillion, three hundred eleven billion, four hundred twenty million, two hundred twenty thousand, one hundred thirteen".
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