Search a number
-
+
323211202103131 is a prime number
BaseRepresentation
bin100100101111101010111100…
…0111000111000011101011011
31120101101200121101200212001221
41021133111320320320131123
5314330443020214300011
63103225102035552511
7125036144615152636
oct11137257070703533
91511350541625057
10323211202103131
1193a92112541301
12303005b575b737
1310b468bb2a48b4
1459b571170ac1d
1527576e9a6e971
hex125f578e3875b

323211202103131 has 2 divisors, whose sum is σ = 323211202103132. Its totient is φ = 323211202103130.

The previous prime is 323211202103051. The next prime is 323211202103201. The reversal of 323211202103131 is 131301202112323.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 323211202103131 - 27 = 323211202103003 is a prime.

It is a super-2 number, since 2×3232112021031312 (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 323211202103096 and 323211202103105.

It is not a weakly prime, because it can be changed into another prime (323211202101131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161605601051565 + 161605601051566.

It is an arithmetic number, because the mean of its divisors is an integer number (161605601051566).

Almost surely, 2323211202103131 is an apocalyptic number.

323211202103131 is a deficient number, since it is larger than the sum of its proper divisors (1).

323211202103131 is an equidigital number, since it uses as much as digits as its factorization.

323211202103131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 323211202103131 its reverse (131301202112323), we get a palindrome (454512404215454).

The spelling of 323211202103131 in words is "three hundred twenty-three trillion, two hundred eleven billion, two hundred two million, one hundred three thousand, one hundred thirty-one".