Base | Representation |
---|---|
bin | 100100101111101011000000… |
… | …0000010010000101001111011 |
3 | 1120101101200220202022100110101 |
4 | 1021133112000002100221323 |
5 | 314330443241413031133 |
6 | 3103225122001500231 |
7 | 125036150602243306 |
oct | 11137260002205173 |
9 | 1511350822270411 |
10 | 323211322002043 |
11 | 93a92174194112 |
12 | 30300629941677 |
13 | 10b4690a0947b7 |
14 | 59b57235dbb3d |
15 | 275770535537d |
hex | 125f580090a7b |
323211322002043 has 2 divisors, whose sum is σ = 323211322002044. Its totient is φ = 323211322002042.
The previous prime is 323211322001987. The next prime is 323211322002077. The reversal of 323211322002043 is 340200223112323.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 323211322002043 - 217 = 323211321870971 is a prime.
It is a super-3 number, since 3×3232113220020433 (a number of 45 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (323211322002143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161605661001021 + 161605661001022.
It is an arithmetic number, because the mean of its divisors is an integer number (161605661001022).
Almost surely, 2323211322002043 is an apocalyptic number.
323211322002043 is a deficient number, since it is larger than the sum of its proper divisors (1).
323211322002043 is an equidigital number, since it uses as much as digits as its factorization.
323211322002043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 323211322002043 its reverse (340200223112323), we get a palindrome (663411545114366).
The spelling of 323211322002043 in words is "three hundred twenty-three trillion, two hundred eleven billion, three hundred twenty-two million, two thousand, forty-three".
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