Base | Representation |
---|---|
bin | 100100110000011010000001… |
… | …1100001011100011110001011 |
3 | 1120101202100120221020222211101 |
4 | 1021200310003201130132023 |
5 | 314334122103413140021 |
6 | 3103343343101042231 |
7 | 125046354332144053 |
oct | 11140640341343613 |
9 | 1511670527228741 |
10 | 323312312240011 |
11 | 94020a885856a6 |
12 | 30318113256377 |
13 | 10b532b2aa3c63 |
14 | 59ba583d88563 |
15 | 275a166493a91 |
hex | 1260d0385c78b |
323312312240011 has 2 divisors, whose sum is σ = 323312312240012. Its totient is φ = 323312312240010.
The previous prime is 323312312239981. The next prime is 323312312240033. The reversal of 323312312240011 is 110042213213323.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 323312312240011 - 235 = 323277952501643 is a prime.
It is a super-3 number, since 3×3233123122400113 (a number of 45 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (323312312240041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161656156120005 + 161656156120006.
It is an arithmetic number, because the mean of its divisors is an integer number (161656156120006).
Almost surely, 2323312312240011 is an apocalyptic number.
323312312240011 is a deficient number, since it is larger than the sum of its proper divisors (1).
323312312240011 is an equidigital number, since it uses as much as digits as its factorization.
323312312240011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 323312312240011 its reverse (110042213213323), we get a palindrome (433354525453334).
The spelling of 323312312240011 in words is "three hundred twenty-three trillion, three hundred twelve billion, three hundred twelve million, two hundred forty thousand, eleven".
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