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323313312102017 is a prime number
BaseRepresentation
bin100100110000011010011111…
…1000111100111011010000001
31120101202110011121200020122112
41021200310333013213122001
5314334131130344231032
63103344030215345105
7125046421162631456
oct11140647707473201
91511673147606575
10323313312102017
1194021450a14836
1230318352082195
1310b53411c93393
1459ba63aa9b82d
15275a1c41491b2
hex1260d3f1e7681

323313312102017 has 2 divisors, whose sum is σ = 323313312102018. Its totient is φ = 323313312102016.

The previous prime is 323313312101963. The next prime is 323313312102083. The reversal of 323313312102017 is 710201213313323.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 303639128459536 + 19674183642481 = 17425244^2 + 4435559^2 .

It is a cyclic number.

It is not a de Polignac number, because 323313312102017 - 214 = 323313312085633 is a prime.

It is a super-2 number, since 2×3233133121020172 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (323313312302017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161656656051008 + 161656656051009.

It is an arithmetic number, because the mean of its divisors is an integer number (161656656051009).

Almost surely, 2323313312102017 is an apocalyptic number.

It is an amenable number.

323313312102017 is a deficient number, since it is larger than the sum of its proper divisors (1).

323313312102017 is an equidigital number, since it uses as much as digits as its factorization.

323313312102017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13608, while the sum is 32.

The spelling of 323313312102017 in words is "three hundred twenty-three trillion, three hundred thirteen billion, three hundred twelve million, one hundred two thousand, seventeen".