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323402123131 is a prime number
BaseRepresentation
bin1001011010011000100…
…01001100011101111011
31010220202110011001120021
410231030101030131323
520244311420420011
6404322513511311
732236130455513
oct4551421143573
91126673131507
10323402123131
1111517708182a
1252816872537
132465c2c3849
141191d1c8843
15862be51471
hex4b4c44c77b

323402123131 has 2 divisors, whose sum is σ = 323402123132. Its totient is φ = 323402123130.

The previous prime is 323402123123. The next prime is 323402123137. The reversal of 323402123131 is 131321204323.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 323402123131 - 23 = 323402123123 is a prime.

It is a super-2 number, since 2×3234021231312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 323402123096 and 323402123105.

It is not a weakly prime, because it can be changed into another prime (323402123137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161701061565 + 161701061566.

It is an arithmetic number, because the mean of its divisors is an integer number (161701061566).

Almost surely, 2323402123131 is an apocalyptic number.

323402123131 is a deficient number, since it is larger than the sum of its proper divisors (1).

323402123131 is an equidigital number, since it uses as much as digits as its factorization.

323402123131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 323402123131 its reverse (131321204323), we get a palindrome (454723327454).

The spelling of 323402123131 in words is "three hundred twenty-three billion, four hundred two million, one hundred twenty-three thousand, one hundred thirty-one".