Base | Representation |
---|---|
bin | 101111000100000110001… |
… | …011110011011011111011 |
3 | 102110012001221110220220021 |
4 | 233010012023303123323 |
5 | 410442132304201301 |
6 | 10513435533111311 |
7 | 452443561345342 |
oct | 57040613633373 |
9 | 12405057426807 |
10 | 3234214131451 |
11 | 103769361a276 |
12 | 44298b928537 |
13 | 1a5ca62ca074 |
14 | b2772d96b59 |
15 | 591e17638a1 |
hex | 2f1062f36fb |
3234214131451 has 2 divisors, whose sum is σ = 3234214131452. Its totient is φ = 3234214131450.
The previous prime is 3234214131443. The next prime is 3234214131493. The reversal of 3234214131451 is 1541314124323.
3234214131451 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3234214131451 - 23 = 3234214131443 is a prime.
It is not a weakly prime, because it can be changed into another prime (3234214131151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1617107065725 + 1617107065726.
It is an arithmetic number, because the mean of its divisors is an integer number (1617107065726).
Almost surely, 23234214131451 is an apocalyptic number.
3234214131451 is a deficient number, since it is larger than the sum of its proper divisors (1).
3234214131451 is an equidigital number, since it uses as much as digits as its factorization.
3234214131451 is an evil number, because the sum of its binary digits is even.
The product of its digits is 34560, while the sum is 34.
Adding to 3234214131451 its reverse (1541314124323), we get a palindrome (4775528255774).
The spelling of 3234214131451 in words is "three trillion, two hundred thirty-four billion, two hundred fourteen million, one hundred thirty-one thousand, four hundred fifty-one".
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