Base | Representation |
---|---|
bin | 101111000100001100101… |
… | …001101100100111101001 |
3 | 102110012100111122021111110 |
4 | 233010030221230213221 |
5 | 410442343043144040 |
6 | 10513454410420533 |
7 | 452446346521104 |
oct | 57041451544751 |
9 | 12405314567443 |
10 | 3234322631145 |
11 | 1037739896741 |
12 | 442a00131749 |
13 | 1a5cc2928578 |
14 | b278355b73b |
15 | 591eb046980 |
hex | 2f10ca6c9e9 |
3234322631145 has 16 divisors (see below), whose sum is σ = 5194153823040. Its totient is φ = 1718559532224.
The previous prime is 3234322631143. The next prime is 3234322631203. The reversal of 3234322631145 is 5411362234323.
3234322631145 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3234322631145 - 21 = 3234322631143 is a prime.
It is a super-2 number, since 2×32343226311452 (a number of 26 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (3234322631143) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 400779439 + ... + 400787508.
It is an arithmetic number, because the mean of its divisors is an integer number (324634613940).
Almost surely, 23234322631145 is an apocalyptic number.
It is an amenable number.
3234322631145 is a deficient number, since it is larger than the sum of its proper divisors (1959831191895).
3234322631145 is a wasteful number, since it uses less digits than its factorization.
3234322631145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 801567224.
The product of its digits is 311040, while the sum is 39.
Adding to 3234322631145 its reverse (5411362234323), we get a palindrome (8645684865468).
The spelling of 3234322631145 in words is "three trillion, two hundred thirty-four billion, three hundred twenty-two million, six hundred thirty-one thousand, one hundred forty-five".
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