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3240442034113 = 24508713221599
BaseRepresentation
bin101111001001111001011…
…001010111011111000001
3102110210010222101011020211
4233021321121113133001
5411042411130042423
610520345530434121
7453054113553064
oct57117131273701
912423128334224
103240442034113
11103a29a060769
12444029592941
131a675966c57b
14b2ba416c8db
15594583b810d
hex2f2796577c1

3240442034113 has 4 divisors (see below), whose sum is σ = 3240455500800. Its totient is φ = 3240428567428.

The previous prime is 3240442034101. The next prime is 3240442034161. The reversal of 3240442034113 is 3114302440423.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3240442034113 - 213 = 3240442025921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3240442034513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6365713 + ... + 6855886.

It is an arithmetic number, because the mean of its divisors is an integer number (810113875200).

Almost surely, 23240442034113 is an apocalyptic number.

It is an amenable number.

3240442034113 is a deficient number, since it is larger than the sum of its proper divisors (13466687).

3240442034113 is a wasteful number, since it uses less digits than its factorization.

3240442034113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13466686.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 3240442034113 its reverse (3114302440423), we get a palindrome (6354744474536).

The spelling of 3240442034113 in words is "three trillion, two hundred forty billion, four hundred forty-two million, thirty-four thousand, one hundred thirteen".

Divisors: 1 245087 13221599 3240442034113