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3241433241953 is a prime number
BaseRepresentation
bin101111001010110100011…
…110100001100101100001
3102110212201001111201210022
4233022310132201211201
5411101423402220303
610521032135443225
7453120510644624
oct57126436414541
912425631451708
103241433241953
11103a7586198a5
12444265526515
131a6886b1b89a
14b2c59a6bdbb
15594b540e438
hex2f2b47a1961

3241433241953 has 2 divisors, whose sum is σ = 3241433241954. Its totient is φ = 3241433241952.

The previous prime is 3241433241947. The next prime is 3241433242037. The reversal of 3241433241953 is 3591423341423.

3241433241953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3240532821904 + 900420049 = 1800148^2 + 30007^2 .

It is a cyclic number.

It is not a de Polignac number, because 3241433241953 - 26 = 3241433241889 is a prime.

It is not a weakly prime, because it can be changed into another prime (3241433241913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1620716620976 + 1620716620977.

It is an arithmetic number, because the mean of its divisors is an integer number (1620716620977).

Almost surely, 23241433241953 is an apocalyptic number.

It is an amenable number.

3241433241953 is a deficient number, since it is larger than the sum of its proper divisors (1).

3241433241953 is an equidigital number, since it uses as much as digits as its factorization.

3241433241953 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 933120, while the sum is 44.

The spelling of 3241433241953 in words is "three trillion, two hundred forty-one billion, four hundred thirty-three million, two hundred forty-one thousand, nine hundred fifty-three".