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324147250041 = 3108049083347
BaseRepresentation
bin1001011011110001010…
…11101000001101111001
31010222200101020102112020
410231320223220031321
520302323144000131
6404524452305053
732263446110256
oct4557053501571
91128611212466
10324147250041
1111551974369a
12529a4312189
132474a7a3244
141199014c42d
158672589996
hex4b78ae8379

324147250041 has 4 divisors (see below), whose sum is σ = 432196333392. Its totient is φ = 216098166692.

The previous prime is 324147249989. The next prime is 324147250051. The reversal of 324147250041 is 140052741423.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-324147250041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 324147249984 and 324147250011.

It is not an unprimeable number, because it can be changed into a prime (324147250051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54024541671 + ... + 54024541676.

It is an arithmetic number, because the mean of its divisors is an integer number (108049083348).

Almost surely, 2324147250041 is an apocalyptic number.

It is an amenable number.

324147250041 is a deficient number, since it is larger than the sum of its proper divisors (108049083351).

324147250041 is a wasteful number, since it uses less digits than its factorization.

324147250041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 108049083350.

The product of its (nonzero) digits is 26880, while the sum is 33.

Adding to 324147250041 its reverse (140052741423), we get a palindrome (464199991464).

The spelling of 324147250041 in words is "three hundred twenty-four billion, one hundred forty-seven million, two hundred fifty thousand, forty-one".

Divisors: 1 3 108049083347 324147250041