Base | Representation |
---|---|
bin | 101111001011101011001… |
… | …001101101011101000111 |
3 | 102110222001222112220202102 |
4 | 233023223021231131013 |
5 | 411110313214014143 |
6 | 10521303144302315 |
7 | 453152316536102 |
oct | 57135311553507 |
9 | 12428058486672 |
10 | 3242350532423 |
11 | 10400893907a2 |
12 | 44448077199b |
13 | 1a69a1b8a302 |
14 | b2d05809739 |
15 | 5951ac040b8 |
hex | 2f2eb26d747 |
3242350532423 has 16 divisors (see below), whose sum is σ = 3326895596640. Its totient is φ = 3158069990400.
The previous prime is 3242350532387. The next prime is 3242350532459.
3242350532423 is nontrivially palindromic in base 10.
It is an interprime number because it is at equal distance from previous prime (3242350532387) and next prime (3242350532459).
It is a cyclic number.
It is not a de Polignac number, because 3242350532423 - 236 = 3173631055687 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3242350531423) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 62244233 + ... + 62296301.
It is an arithmetic number, because the mean of its divisors is an integer number (207930974790).
Almost surely, 23242350532423 is an apocalyptic number.
3242350532423 is a deficient number, since it is larger than the sum of its proper divisors (84545064217).
3242350532423 is a wasteful number, since it uses less digits than its factorization.
3242350532423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54578.
The product of its (nonzero) digits is 518400, while the sum is 38.
It can be divided in two parts, 3242350 and 532423, that added together give a palindrome (3774773).
The spelling of 3242350532423 in words is "three trillion, two hundred forty-two billion, three hundred fifty million, five hundred thirty-two thousand, four hundred twenty-three".
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