Base | Representation |
---|---|
bin | 1001011100001010000… |
… | …00011001100010011011 |
3 | 1011000012210022111200120 |
4 | 10232011000121202123 |
5 | 20303234112142111 |
6 | 405001200204323 |
7 | 32301536456511 |
oct | 4560500314233 |
9 | 1130183274616 |
10 | 324354021531 |
11 | 115615431121 |
12 | 52a416096a3 |
13 | 2478158b737 |
14 | 119ad7b44b1 |
15 | 86857d0406 |
hex | 4b8501989b |
324354021531 has 4 divisors (see below), whose sum is σ = 432472028712. Its totient is φ = 216236014352.
The previous prime is 324354021517. The next prime is 324354021569. The reversal of 324354021531 is 135120453423.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-324354021531 is a prime.
It is a super-2 number, since 2×3243540215312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 324354021492 and 324354021501.
It is not an unprimeable number, because it can be changed into a prime (324354021581) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54059003586 + ... + 54059003591.
It is an arithmetic number, because the mean of its divisors is an integer number (108118007178).
Almost surely, 2324354021531 is an apocalyptic number.
324354021531 is a deficient number, since it is larger than the sum of its proper divisors (108118007181).
324354021531 is a wasteful number, since it uses less digits than its factorization.
324354021531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 108118007180.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 324354021531 its reverse (135120453423), we get a palindrome (459474474954).
The spelling of 324354021531 in words is "three hundred twenty-four billion, three hundred fifty-four million, twenty-one thousand, five hundred thirty-one".
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