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32440320421433 is a prime number
BaseRepresentation
bin1110110000001000110011…
…10001100110111000111001
311020212021010201002121111222
413120010121301212320321
513223000234011441213
6152554513311001425
76555510244621331
oct730043161467071
9136767121077458
1032440320421433
11a377954184681
12377b199809275
131514155892192
14802196d780c1
153b3ca937b808
hex1d8119c66e39

32440320421433 has 2 divisors, whose sum is σ = 32440320421434. Its totient is φ = 32440320421432.

The previous prime is 32440320421423. The next prime is 32440320421529. The reversal of 32440320421433 is 33412402304423.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 32436248450089 + 4071971344 = 5695283^2 + 63812^2 .

It is a cyclic number.

It is not a de Polignac number, because 32440320421433 - 28 = 32440320421177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 32440320421393 and 32440320421402.

It is not a weakly prime, because it can be changed into another prime (32440320421423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16220160210716 + 16220160210717.

It is an arithmetic number, because the mean of its divisors is an integer number (16220160210717).

Almost surely, 232440320421433 is an apocalyptic number.

It is an amenable number.

32440320421433 is a deficient number, since it is larger than the sum of its proper divisors (1).

32440320421433 is an equidigital number, since it uses as much as digits as its factorization.

32440320421433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 165888, while the sum is 35.

Adding to 32440320421433 its reverse (33412402304423), we get a palindrome (65852722725856).

The spelling of 32440320421433 in words is "thirty-two trillion, four hundred forty billion, three hundred twenty million, four hundred twenty-one thousand, four hundred thirty-three".